Rhombus: quadrilateral all of whose sides have the same length.
Area of A Rhombus: A rhombus is actually just a special type of parallelogram. The "base times height" method: First pick one side to be the base. Any one will do, they are all the same length. Then determine the altitude - the perpendicular distance from the chosen base to the opposite side. The area is the product of these two, or, as a formula: Area = base x height:.
The "diagonals" method: Another simple formula for the area of a rhombus when you know the lengths of the diagonals. The area is half the product of the diagonals. As a formula: Area = where, d1 is the length of a diagonal and d2 is the length of the other diagonal
Example: Find the area of a rhombus having each side equal to 13 cm and one of whose deiagonals is 24 cm. Solution : Let ABCD be the given parallelogram whose diagonals intersect at O. We have, AB = 13 cm and AC = 24 cm. Since the diagonals of a rhombus bisect each other at right angles. Therefore, AOB is a right triangle, right angled at O such that and AB = 13cm. Using Pythagoras theorem, in AOB, we have = + = + = - = 169 - 144 = 25 = Hence, OB = 5 cm Also, BD = 2 x OB = 10cm Hence , Area of rhombus ABCD = |
The area of rhombus of diagonal 8 cm & 4 cm is ____________ c | |||
Right Option : B | |||
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The diagonals of a rhombus are 8 cm and 10 cm. Then the area of the rhombus is ______________________. | |||
Right Option : D | |||
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If the length of two diagonal of a rhombus are 12 cm and 16 cm, then the length of each side of the rhombus are : | |||
Right Option : A | |||
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